x^2+32x=4100

Solution for x^2+32x=4100 equation:

x^2+32x=4100

We move all terms to the left:

x^2+32x-(4100)=0

a = 1; b = 32; c = -4100;
Δ = b2-4ac
Δ = 322-4·1·(-4100)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-132}{2*1}=\frac{-164}{2}
=-82
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+132}{2*1}=\frac{100}{2}
=50
$